发明公开
EP0623993A3 Four quadrant multiplier circuit and a receiver including such a circuit
失效
四个象限乘法器和这样的含电路的接收器。
- 专利标题: Four quadrant multiplier circuit and a receiver including such a circuit
- 专利标题(中): 四个象限乘法器和这样的含电路的接收器。
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申请号: EP94200921.8申请日: 1994-04-05
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公开(公告)号: EP0623993A3公开(公告)日: 1995-01-18
- 发明人: Cusdin, Anthony Richard , Moore, Paul Anthony
- 申请人: PHILIPS ELECTRONICS UK LIMITED , Philips Electronics N.V.
- 申请人地址: 420-430 London Road Croydon CR9 3QR GB
- 专利权人: PHILIPS ELECTRONICS UK LIMITED,Philips Electronics N.V.
- 当前专利权人: PHILIPS ELECTRONICS UK LIMITED,Philips Electronics N.V.
- 当前专利权人地址: 420-430 London Road Croydon CR9 3QR GB
- 代理机构: Moody, Colin James
- 优先权: GB9307384 19930408
- 主分类号: H03D3/00
- IPC分类号: H03D3/00 ; G06G7/163
摘要:
A four quadrant multiplier circuit having a high dynamic range and capable of operating at low voltages comprises a dual transconductance amplifier circuit (TAC) consisting of NPN transistors (20 to 23 and 64 to 67), coupled to a first input port (36), first and second folded Darlington circuits (57,58), and a resistive element (78). Each said Darlington circuit comprises first and second NPN transistors (68,70 and 69,71) whose emitter-collector paths are connected in series and a third PNP transistor (72,73) having its emitter-collector path connected between the collector of the first transistor (68,69) and the base electrode of the second transistor (70,71). The emitter-collector junction (76,77) of the first and second transistors (68,70 and 69,71) is connected to the base electrode of the third transistor (72,73). The resistive element (78) is connected between the base electrodes of the third transistors (72,73). A second input port (56) is connected to the base electrodes of the first transistors (68,69). The emitter currents of the dual transconductance amplifier are supplied by way of current mirror circuits (80,81) from the emitter currents of the second transistors (70,71). The transconductance amplifier circuit (TAC) may be of any suitable type which has its transconductance linearly proportional to its emitter currents. In a refinement of the circuit, the current to voltage converter function of the current mirrors is carried out by the second transistors (70,71) and the transistors (82,83) of the current mirror circuits (80,81) are omitted.
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