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    Method for converting UO3 or U3O8 into hydrated UO4
    1.
    发明授权
    Method for converting UO3 or U3O8 into hydrated UO4 有权
    将UO3或U3O8转化为水合UO4的方法

    公开(公告)号：US09045350B2

    公开(公告)日：2015-06-02

    申请号：US13995277

    申请日：2011-12-16

    申请人： Bertrand Morel ,  David Amaraggi ,  Mehdi Arab ,  Rudy Thomas ,  Murielle Rivenet ,  Francis Abraham

    发明人： Bertrand Morel ,  David Amaraggi ,  Mehdi Arab ,  Rudy Thomas ,  Murielle Rivenet ,  Francis Abraham

    IPC分类号： C01G43/01 ,  C01B15/047 ,  C01G43/06

    CPC分类号： C01G43/01 ,  C01B15/0475 ,  C01G43/06 ,  C01P2002/72 ,  C01P2004/03 ,  C01P2004/10 ,  C01P2004/54 ,  C01P2006/12

    摘要： A method for converting UO3 and/or U3O8 into hydrated UO4 of formula UO4.nH2O wherein n is 2 or 4, comprising the following successive steps: a) preparing an aqueous suspension of a UO3 powder and/or a U3O8 powder; b) adding hydrogen peroxide H2O2 to the aqueous suspension of a UO3 and/or U3O8 powder, converting the UO3 and/or U3O8 into hydrated UO4 and precipitating, crystallizing the hydrated UO4 in the suspension; c) recovering the precipitate, crystals of UO4 hydrate; d) optionally, washing the recovered UO4 hydrate precipitate, crystal(s); e) optionally, repeating step d); f) optionally, drying the precipitate, the crystals; wherein the addition of H2O2 to the aqueous suspension is carried out so that the suspension contains a stoichiometric excess of H2O2 relatively to the stoichiometry of the reaction from UO3: UO3+nH2O+H2O2→UO4.nH2O+H2O  (1) or of the reaction from U3O8 UO2.67+1.33H2O2+nH2O→UO4.nH2O+1.33H2O  (2), and the pH of the suspension is maintained in steps a) and b) at a value comprised between 2 and 3.

    摘要翻译： 将UO 3和/或U 3 O 8转化为式UO·4H 2 O的水合UO 4的方法，其中n为2或4，包括以下连续步骤：a）制备UO 3粉末和/或U 3 O 8粉末的水性悬浮液; b）向UO 3和/或U 3 O 8粉末的水性悬浮液中加入过氧化氢H 2 O 2，将UO 3和/或U 3 O 8转化为水合UO 4并沉淀，使悬浮液中的水合UO4结晶; c）回收沉淀物，UO4水合物晶体; d）任选地，洗涤回收的UO4水合物沉淀物，晶体; e）任选地，重复步骤d）; f）任选地，干燥沉淀物，晶体; 其中向含水悬浮液中加入H 2 O 2使得悬浮液相对于来自UO 3 :OO 3 + nH 2 O + H 2 O 2→UO 4·n H 2 O + H 2 O（1）或反应的反应的化学计量比含有化学计量过量的H 2 O 2 从U3O8 UO2.67 + 1.33H2O2 + nH2O→UO4·nH2O + 1.33H2O（2），并且悬浮液的pH在步骤a）和b）中保持在2和3之间的值。

    METHOD FOR CONVERTING UO3 OR U3O8 INTO HYDRATED UO4
    2.
    发明申请
    METHOD FOR CONVERTING UO3 OR U3O8 INTO HYDRATED UO4 有权
    将UO3或U3O8转化为水合UO4的方法

    公开(公告)号：US20130280157A1

    公开(公告)日：2013-10-24

    申请号：US13995277

    申请日：2011-12-16

    申请人： Bertrand Morel ,  David Amaraggi ,  Mehdi Arab ,  Rudy Thomas ,  Murielle Rivenet ,  Francis Abraham

    发明人： Bertrand Morel ,  David Amaraggi ,  Mehdi Arab ,  Rudy Thomas ,  Murielle Rivenet ,  Francis Abraham

    IPC分类号： C01G43/01

    CPC分类号： C01G43/01 ,  C01B15/0475 ,  C01G43/06 ,  C01P2002/72 ,  C01P2004/03 ,  C01P2004/10 ,  C01P2004/54 ,  C01P2006/12

    摘要： A method for converting UO3 and/or U3O8 into hydrated UO4 of formula UO4.nH2O wherein n is 2 or 4, comprising the following successive steps: a) preparing an aqueous suspension of a UO3 powder and/or a U3O8 powder; b) adding hydrogen peroxide H2O2 to the aqueous suspension of a UO3 and/or U3O8 powder, converting the UO3 and/or U3O8 into hydrated UO4 and precipitating, crystallizing the hydrated UO4 in the suspension; g) recovering the precipitate, crystals of UO4 hydrate; h) optionally, washing the recovered UO4 hydrate precipitate, crystal(s); i) optionally, repeating step d); j) optionally, drying the precipitate, the crystals; wherein the addition of H2O2 to the aqueous suspension is carried out so that the suspension contains a stoichiometric excess of H2O2 relatively to the stoichiometry of the reaction from UO3: UO3+nH2O+H2O2→UO4.nH2O+H2O  (1) or of the reaction from U3O8 UO2.67+1.33H2O2+nH2O→UO4.nH2O+H2O  (2) and the pH of the suspension is maintained in steps a) and b) at a value comprised between 2 and 3.

    摘要翻译： 将UO 3和/或U 3 O 8转化为式UO·4H 2 O的水合UO 4的方法，其中n为2或4，包括以下连续步骤：a）制备UO 3粉末和/或U 3 O 8粉末的水性悬浮液; b）向UO 3和/或U 3 O 8粉末的水性悬浮液中加入过氧化氢H 2 O 2，将UO 3和/或U 3 O 8转化为水合UO 4并沉淀，使悬浮液中的水合UO4结晶; g）回收沉淀物，UO4水合物晶体; h）任选地，洗涤回收的UO4水合物沉淀物，晶体; i）任选地，重复步骤d）; j）任选地，干燥沉淀物，晶体; 其中向含水悬浮液中加入H 2 O 2使得悬浮液相对于来自UO 3 :OO 3 + n H 2 O + H 2 O 2→UO 4·n H 2 O + H 2 O（1）的反应的化学计量比，含有化学计量过量的H 2 O 2 来自U3O8 UO2.67 + 1.33H2O2 + nH2O-> UO4·nH2O + H2O（2）的反应，并且悬浮液的pH在步骤a）和b）中保持在2和3之间的值。