PROCESS FOR PRODUCTION OF FLUOROALKYL IODIDE
    2.
    发明公开
    PROCESS FOR PRODUCTION OF FLUOROALKYL IODIDE 有权
    VERFAHREN ZUR HERSTELLUNG VON FLUORALKYL-IODID

    公开(公告)号:EP2578560A1

    公开(公告)日:2013-04-10

    申请号:EP11789901.3

    申请日:2011-06-02

    IPC分类号: C07C17/281 C07C19/16

    摘要: To provide a process for producing a fluoroalkyl iodide, whereby the selectivity for a fluoroalkyl iodide having a desired degree of polymerization is high and the productivity is high. A process for producing a fluoroalkyl iodide (2) represented by R f CF 2 CF 2 I (wherein R f is a fluoroalkyl group having at most 4 carbon atoms), which comprises reacting a fluoroalkyl iodide (1) represented by R f I with tetrafluoroethylene in the presence of a radical initiator, wherein a first reaction step of supplying and reacting tetrafluoroethylene and a radical initiator to the fluoroalkyl iodide (1), is followed by repeating (n-1) times (provided that n is an integer of at least 3) a subsequent reaction step of supplying and reacting a radical initiator, or a radical initiator and tetrafluoroethylene, to a reaction mixture (1) formed in the first reaction step.

    摘要翻译: 为了提供一种制备氟代烷基碘的方法,由此对具有所需聚合度的氟代烷基碘的选择性高,生产率高。 一种制备由R f CF 2 CF 2 I(其中R f为至多4个碳原子的氟烷基)表示的氟烷基碘化物(2)的方法,其包括将由R f I表示的氟代烷基碘(1)与 四氟乙烯在自由基引发剂的存在下反应,其中将四氟乙烯和自由基引发剂供应和反应到氟代烷基碘(1)的第一反应步骤之后是重复(n-1)次(条件是n是在 至少3)随后的反应步骤,其将自由基引发剂或自由基引发剂和四氟乙烯供应到反应混合物(1)中并在第一反应步骤中形成。

    Process for purifying pentafluoroethane from chloropentafluoroethane
    5.
    发明公开
    Process for purifying pentafluoroethane from chloropentafluoroethane 有权
    Abtrennung von Chlorpentafluorethan aus Pentafluorethan

    公开(公告)号:EP1070697A1

    公开(公告)日:2001-01-24

    申请号:EP00115289.1

    申请日:2000-07-14

    申请人: Ausimont S.p.A.

    IPC分类号: C07C17/395 C07C19/08

    摘要: A gaseous process for reducing the amount of chloropentafluoroethane (CFC 115) impurity present in pentafluoroethane (HFC 125) characterized in that pentafluroethane is allowed to flow on a catalyst formed by a trivalent chromium salt, optionally supported, at temperatures in the range 200°C-400°C, obtaining the reaction of chloropentafluoroethane with pentafluoroethane with formation of hexafluoroethane (FC 116) and tetrafluorochloroethane (HCFC 124).

    摘要翻译: 用于减少五氟乙烷(HFC 125)中存在的氯五氟乙烷(CFC 115)杂质的量的气体方法,其特征在于使五氟乙烷在任选负载的三价铬盐形成的催化剂上流动,温度范围为200℃ -400℃,得到五氟乙烷与五氟乙烷反应生成六氟乙烷(FC 116)和四氟氯乙烷(HCFC 124)。

    Process for eliminating chlorine from chlorofluorocarbons
    6.
    发明公开
    Process for eliminating chlorine from chlorofluorocarbons 有权
    从含氯氟烃中除去氯的过程

    公开(公告)号:EP1070696A2

    公开(公告)日:2001-01-24

    申请号:EP00115288.3

    申请日:2000-07-14

    申请人: Ausimont S.p.A.

    IPC分类号: C07C17/23 C07C19/08 C07C17/20

    摘要: A gaseous process for eliminating chlorine atoms from a chlorofluorocarbon (CFC) of formula C n F x Cl y , wherein n is an integer from 1 to 3 and x + y = 2n + 2 , wherein said compound is reacted with an hydrofluorocarbon of formula C n' F x' H y' wherein n', x', y' are as above defined, in the presence of a fluorination catalyst in solid phase at temperatures in the range 200°C-400°C.

    摘要翻译: 用于从式CnFxCly的氯氟烃(CFC)中除去氯原子的气体方法,其中n是1至3的整数并且x + y = 2n + 2,其中所述化合物与式Cn'Fx'Hy的氢氟烃 其中n',x',y'如上所定义,在固相氟化催化剂存在下在200-400℃范围内的温度下进行。

    Catalytic transhalogenation of haloaromatics
    10.
    发明公开
    Catalytic transhalogenation of haloaromatics 失效
    卤代芳烃的催化卤代反应

    公开(公告)号:EP0233035A1

    公开(公告)日:1987-08-19

    申请号:EP87300924.5

    申请日:1987-02-03

    摘要: Catalytic transhalogenation of haloaromatics according to the equation:
    wherein

    when C z is a benzene derivative,
    a+b=5; e=0; c+d=5; z=6;
    when C z is a pyridine derivative,
    a+b=4; e=1; c+d=4; z=5;
    when C z is a naphthalene derivative,
    a+b=7; e=0; c+d=7; z=10; and
    when C z is a biphenyl derivative,
    a+b=9; e=0; c+d=9; z=12;
    Li and L 2 , alike or different, are selected from F, Cl, Br,
    H, CN, C n F 2n+1 , and C 6 F 5 ;
    X is Cl, Br, or I when C z is a benzene derivative; and n is 1 to 12

    摘要翻译: 根据以下方程式进行卤代芳族化合物的卤化催化反应:其中当Cz为苯衍生物时,a + b = 5; E = 0; C + d = 5; Z = 6; 当Cz是吡啶衍生物时,a + b = 4; E = 1; C + d = 4; Z = 5; 当Cz是萘衍生物时,a + b = 7; E = 0; C + d = 7; Z = 10; 当Cz是联苯衍生物时,a + b = 9; E = 0; C + d = 9; Z = 12; Li和L2相同或不同,选自F,Cl,Br,H,CN,CnF2n + 1和C6F5; 当Cz是苯衍生物时,X是Cl,Br或I; 并且n是1至12